Solving inequality MX ^ 2-2x + 1 > 0

Solving inequality MX ^ 2-2x + 1 > 0


When m > 1, the solution set is R. when m = 1, the solution set is: X is not equal to 1



2X ^ 2 + MX-1 ≥ 0,


b^2-4ac=m^2-4*2*(-1)=m^2+8>0
So the equation 2x ^ 2 + MX-1 = 0 has two different roots
X1 = (- M + m ^ 2 + 8 under radical) / 4
X2 = (- m-root m ^ 2 + 8) / 4
So the solution of the inequality is x > = X1 or X



Solving inequality, MX ^ 2 + 2x + 1


Using the root formula
So X1 = [- 1-radical (1-m)] / M x2 = [- 1 + radical (1-m)] / M
Because 1-m > = 0
So m

Elden Ring Premiere

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