0.1X + 0.2x + 0.5 (38-2x) = 9.2 calculate the process! Be clear, fast! 1

0.1X + 0.2x + 0.5 (38-2x) = 9.2 calculate the process! Be clear, fast! 1

Original formula = 0.3x + 19-x = 9,2
The deformation is as follows
-0.7x=9.2-19=-9.8
The solution is x = 14

Calculate 2x-2 + X-1 / 5
calculation

2X-2+X-1／5
=3x-11/5;
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How to solve (xsquare x 1) / (xsquare 1) (2xquare x 2) / (xsquare x 1) = 19 / 6

(xsquare x 1) / (xsquare 1) (2xquare x 2) / (xsquare x 1) = 19 / 6
1 times 4 x = 19 / 6
4 X=19/6
X= 38/3

1.5x squared - (- 0.5x squared) + (- 2x squared)

1.5x squared - (- 0.5x squared) + (- 2x squared)
=1.5x^2+0.5x^2-2x^2
=0

In the square y-5x = 0 of 1 / 2x, the coefficient of the square y term of 1 / 2x is?, the number of times is?, 0 is?, and the number of times is once?

1 / 2x, where y-5x = 0,
The coefficient of the square y term of 1 / 2x is 1 / 2,
The number of times is three,
0 is a constant term,
The term whose number is once is - 5x

The square formula of 2x (2x-y) - Y (y-2x)

The square of 2x (2x-y) - the square of Y (y-2x) = (2x-y) (4x ^ 2 + y ^ 2-4xy) = 8x ^ 3 + 2XY ^ 2-8x ^ 2y-4x ^ 2y-y ^ 3 + 4xy ^ 2

The square of (3x-y) - (2x + y) + 5x (Y-X) is a process

The square of (y-2x + 5x)
=9x²-6xy+y²-(4x²+4xy+y²)+5xy-5x²
=-5xy

The square of 5x - 4xy + the square of Y + 2x + 1 = 0 to find the x-square of Y

That is, (4x & # 178; - 4xy + Y & # 178;) + (X & # 178; + 2x + 1) = 0
(2x-y)²+(x+1)²=0
therefore
2x-y=0,x+1=0
x=-1
y=2x=-2
So the - power of the original formula = (- 2) = - 1 / 2

Formula x squared - 5x + 7

Original formula = x & # 178; - 5x + 25 / 4-25 / 4 + 7
=(x-5/2)²+3/4

Formula: square of x-5x-10

Solution
x²-5x-10
=(x²-5x+25/4)-25/4-10
=(x-5/2)²-65/4