The square of (2x + 1) - 5 = 0 (factorization)

The square of (2x + 1) - 5 = 0 (factorization)

4x²+4x-4=0
4(x²+x-1)=0

2 (2x-1) square + 5 (2x-1) - 12 = 0

That is [2 (2x-1) - 3] [(2x-1) + 4] = 0
(4x-5)(2x+3)=0
x=5/4,x=-3/2

Given the set a = {x | y square = x + 1}, B = {x | y square = 2x + 6}, find a intersection B, a union B
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Set a = {x | x = y ^ 2-1}
Set B = {x | x = y ^ 2 / 2-3}
x=y^2-1>=-1
x=y^2/2-3>=-3
be
Set a = {x | x > = - 1}
Set B = {x | x > = - 3}
A∩B={x|x>=-1}
A∪B={x|x>=-3}

Square of (x-2x) - 7 (x-2x) - 8

Square of (x-2x) - 7 (x-2x) - 8
=(x^2-2x-8)(x^2-2x+1)
=(x-4)(x+2)(x-1)^2

The equation 2x square = (x + 1) is squared into the general form of quadratic equation with one variable

Xsquare - 2x-1 = 0

(5-2x) (2x + 5) + (x + 5) square

(5－2x)(2x＋5)＋(x+5)^2
=25-4x^2+x^2+10x+25
=-3x^2+10x+50

Square of (X-2) = square of (5-2x)
Finding the sum and product of the roots of two real numbers

X-2 = 5-2x leads to x = 7 / 3
X-2 = - (5-2x) gives x = 3
And 16 / 3, product 7

(1) The quadratic power of (1-x) = 9; (2) the quadratic power of (2x-3) - 9 = 16 (find the value of X in the following equation)

(1) The power of (1-x) = the power of 9;
1-x = 9 or 1-x = - 9
X = - 8 or x = 10
(2) (2x-3) - 9 = 16 (find the value of X in the following equation)
2x-3 = 5 or 2x-3 = - 5
X = 4 or x = - 1

Given that x = - 1 is the solution of the equation 4x + m + 7 = 2x + 3, find the square of m-12m + 9

Put x = - 1 in
Then - 4 + m + 7 = - 2 + 3
m+3=1
m=-2
So M & sup2; - 12m + 9
=4+24+9
=37

(2x-1) (x + 3) = (x-1) ^ 2 ^ represents the square. Use the appropriate method to solve

（2x-1)(x+3)=(x-1)²
2x²-x+6x-3=x²-2x+1
x²+7x-4=0
According to X12 = [- 7 ± 7 & # 178; - 4 × 1 × (- 4)] / 2 × 1
x12=(-7±√65) /2
x1 =(-7+√65)/2
x2=(-7-√65)/2