Given that a and B are opposite numbers, and | A-B | = 4 / 5, (1) find the value of a-Ab + B / AB ^ 2 + A-B ^ 2A + 1, (2) if | A-B | = B-A, find the value of a-b

Given that a and B are opposite numbers, and | A-B | = 4 / 5, (1) find the value of a-Ab + B / AB ^ 2 + A-B ^ 2A + 1, (2) if | A-B | = B-A, find the value of a-b

First of all, write clearly,
Second question: | A-B | = B-A > 0 (absolute value greater than zero), so A-B = - (B-A) = - | A-B | = - 4 / 5

It is known that (a + 2) &# 178; + B + 3 = 0, find 1 / 3 (9ab & # 178; - 3) + (7a & # 178; b-2) + 2 (AB & # 178; + 1) - 2A & # 178; b

(a + 2) & # + B + 3 = 0
therefore
(a + 2) & # = 0, B + 3 = 0
a=-2
b=-3
therefore
1/3（9ab²-3）+（7a²b-2）+2（ab²+1）-2a²b
=3ab²-1+7a²b-2+2ab²+2-2a²b
=5ab²+5a²b-1
=5ab(a+b)-1
=5×2×3×（-5）-1
=-150-1
=-151

1. Given the square of (b-2a) - 6 (b-2a) + 9 = 0, then 2a-b = ()
2. In the result of (x + 1) (2x to the second power + ax + 1), the coefficient of X to the second power is - 2, then the value of a is -_____ .
3. Calculate 4 * (the second power of 3 + 1) (the fourth power of 3 + 1) (the eighth power of 3 + 1) (the sixteenth power of 3 + 1) - 1 = () this question of the first year of junior high school. Can you answer this question in detail

The square of (b-2a) - 6 (b-2a) + 9 = 0,
The result is: [(b-2a) - 3] ^ 2 = 0
b-2a=3
2a-b=-3
(2) The coefficient of x ^ 2 is 2 + a = - 2
A=4
(3) Follow up with the third question