Find (4a ^ 2 / 3B ^ - 1 / 3) divided by (- 2 / 3A ^ - 1 / 3B ^ 1 / 3)

Find (4a ^ 2 / 3B ^ - 1 / 3) divided by (- 2 / 3A ^ - 1 / 3B ^ 1 / 3)

The coefficients, a and B are divided by
The answer is
-6ab^-2/3

If the square of a = 3A, then a = 3,

No, there's another value, a = 0

A ＞ - 3, the square of a ＜ - 3a, the value range of a is obtained

a^2

How to calculate the square of (3a + 6) = 0

The square of (3a + 6) = 0
3a+6=0
3a=-6
a=-2

Square of (A-3) + (9-3a)

(a-3)2+(9-3a)
=(a-3)(a-3)+3(3-a)
=(a-3)(a-3)-3(a-3)
=(a-3)(a-3-3)
=(a-3)(a-6)

How to multiply the square of (3a-b) by the square of (3a + b)

The square of (3a-b) multiplied by the square of (3a + b) = [(3a-b) (3a + b)] ^ 2 = (9a ^ 2-B ^ 2) ^ 2 = 81a ^ 4 + B ^ 4-18a ^ 2B ^ 2, the interim ^ 2 is the square and ^ 4 is the fourth power

Given that the square root of 2a is ± 3 and the square of 3A + B-1 is ± 4, find the square root of a + 2B

Because the square root of 2a-1 is plus or minus 3, the square root of 3A + B-1 is plus or minus 4
So 2a-1 = (± 3) 2 = 9
3a+b-1=16
The solution is a = 5, B = 2
A + 2b is 9
The square root of a + 2b is ± 3

Given the function f (x) = LNX of X, find the maximum value of FX

First, we obtain f '(x) = (1-lnx) / X2, Let f' (x) = 0, get x = e, then discuss the monotonicity, monotone increasing on (0, e) and monotone decreasing on (E, positive infinity), so we get the maximum value on e, so the maximum value is f (E) = 1 / E

Given the function f (x) = LNX of X, find the maximum value of FX

f(x)=lnx/x
f'(x)=(lnx/x)'=(1-lnx)/x^2=0
lnx=1,x=e
Maximum 1 / E

The known function FX = LNX – A / X
The monotonicity of function FX is discussed
Let GX = - LNX, if FX > = GX is constant at (0, positive infinity), find the range of A

1
f(x)=lnx-a/x
f'(x)=1/x+a/x²=(ax+1)/x²
When a ≥ 0, f '(x) > 0 holds
Ψ f (x) is an increasing function on (0, + ∞)
When A0 is solved to 00, H (x) increases
∴h(x)min=h(1/e)=2/e*(-1)=-2/e
∴a≤-2/e