As shown in the following figure: in trapezoidal ABCD, the area of triangle AEC is 4, the area of triangle CED is 6, and the area of triangle bed is 9? In the picture, the two diagonals are pulled up and divided into four triangles. There are two diagonals A and C (from left to right) at the top and two diagonals B and D at the bottom. The intersection of the diagonals is e

As shown in the following figure: in trapezoidal ABCD, the area of triangle AEC is 4, the area of triangle CED is 6, and the area of triangle bed is 9? In the picture, the two diagonals are pulled up and divided into four triangles. There are two diagonals A and C (from left to right) at the top and two diagonals B and D at the bottom. The intersection of the diagonals is e

Because it is trapezoid, SABC = SACD (same bottom, same height)
)So saed = 6