P is a point inside the square ABCD and a point e outside the square ABCD. Find the degree of angle BPE P is a point inside the square ABCD, and there is a point e outside the square ABCD, satisfying the angle Abe = angle CBP, be = BP, and finding the degree of angle BPE

∠ABC=∠ABP+∠CBP=90°
∠ABE=∠CBP
∠EBP=∠ABE+∠ABP=∠CBP+∠ABP=90°
And be = BP
So △ EBP is an equilateral right triangle
Therefore, BPE = 45 degree

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