E is a point in the square ABCD, and the triangle Abe is an equilateral triangle, connecting CE and De, then ∠ CBE=____ ,∠DCE=____ ,∠CED=____
The triangle Abe is an equilateral triangle with 30 °, 15 ° and 150 ° ∵ the triangle Abe is an equilateral triangle with 60 ° AB = be = AE and the quadrilateral ABCD is a square with ABC = bad = 90 ° AB = BC = ad ≌ CBE = DAE = 30 ° AB = be = AE = BC = ad ≌ ade ≌ BCE ≌ AED = ≌ ade = ≌ BCE = ≌ BEC = 75 ° C
RELATED INFORMATIONS
- 1. In the square ABCD, there is a point E, △ EAB is an equilateral triangle, ∠ CED = several degrees
- 2. As shown in the figure, given a point E in the square ABCD, and AE = EB = AB, find the degree of ∠ EDC and ∠ ECB
- 3. As shown in the figure, the angle EDC is determined by making an equilateral triangle Abe in square ABCD connecting de and CE=
- 4. As shown in the figure, in the quadrilateral ABCD, point E is on BC, ab ‖ De, ∠ B = 78 ° and ∠ C = 60 °, then the degree of ∠ EDC is () A. 42°B. 60°C. 78°D. 80°
- 5. In ladder ABCD, ad ‖ BC (AD
- 6. In trapezoidal ABCD, AD / / BC, diagonal AC intersects BD at point O, if s △ abd: s △ DBC = 4:9, then △ AOD: △ BOC perimeter ratio
- 7. Point O is a point in the parallelogram ABCD such that ∠ AOB + ∠ cod = 180 ° proves that ∠ OBC = ∠ ODC
- 8. As shown in the figure, two diagonal lines AC and BD of parallelogram ABCD intersect at point O. proof: Triangle AOB congruent triangle cod
- 9. The height of a trapezoid is 4cm, and the upper and lower bottoms are increased by 8cm. How much is the area increased
- 10. A trapezoid has an upper bottom of 8 cm, a lower bottom of 4 cm, and a height of H cm. The area of this trapezoid is () square cm. Two such trapezoids can be used to form a parallelogram with a bottom of () cm and a height of () cm
- 11. 1. As shown in the figure, e is a point in the square ABCD, and △ Abe is an equilateral triangle. Think about the relationship between ∠ DCE and ∠ CEB, and explain the reason. 2 1. As shown in the figure, e is a point in the square ABCD, and △ Abe is an equilateral triangle. Think about the relationship between ∠ DCE and ∠ CEB, and explain the reason 2. As shown in the figure, the upper bottom ad of the isosceles trapezoid ABCD = 1, the lower bottom BC = 3, the diagonal AC ⊥ BD, find the height and length of the isosceles trapezoid
- 12. As shown in the figure, e is an edge point in the square ABCD. If the triangle Abe is an equilateral triangle, find the degree of the angle BCE
- 13. P is a point inside the square ABCD and a point e outside the square ABCD. Find the degree of angle BPE P is a point inside the square ABCD, and there is a point e outside the square ABCD, satisfying the angle Abe = angle CBP, be = BP, and finding the degree of angle BPE
- 14. As shown in the following figure: in trapezoidal ABCD, the area of triangle AEC is 4, the area of triangle CED is 6, and the area of triangle bed is 9? In the picture, the two diagonals are pulled up and divided into four triangles. There are two diagonals A and C (from left to right) at the top and two diagonals B and D at the bottom. The intersection of the diagonals is e
- 15. In known trapezoidal ABCD, ad is parallel to BC, angle ABC = 60 degrees, ab = AD + BC = 4, M is the midpoint, find the size of 1 angle dam, the length of AM and BM
- 16. If the side length of square ABCD is 1 and point P moves on line AC, then the value range of AP & nbsp; · & nbsp; (Pb + PD) is______ .
- 17. Given that the side length of square ABCD is 2 and point P is a point on diagonal AC, the maximum value of (. AP +. BD) ·(. Pb +. PD) is______
- 18. If the parallelogram ABCD and EF cross the focus o, ab = 3, BC = 5 and OE = 2 of the diagonal, what is the perimeter of the parallelogram ADFE
- 19. If AB = 5, BC = 7, OE = 2, then the perimeter of EFDC is () A.14 B.15 C.16 D.18
- 20. In the parallelogram ABCD, if EF passes through the intersection of diagonals o, ab = 4, ad = 3, the perimeter of quadrilateral BCEF = 9.6, the length of of of can be obtained