As shown in the figure, given a point E in the square ABCD, and AE = EB = AB, find the degree of ∠ EDC and ∠ ECB

Because Abe is a regular triangle, so AB = be = EA, angle Abe = bea = EAB = 60 degrees, because ABCD is a square, so ad = AE = EB = be, angle DAB = ABC = 90 degrees, so angle DAE = EBC = 90-60 = 30 degrees, angle CEB = ECB = (180-30) / 2 = 75 degrees, angle ade = DEA = (180-30) / 2 = 75 degrees, angle CDE = 90-75 = 15 degrees, I wish you learn

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1. As shown in the figure, the angle EDC is determined by making an equilateral triangle Abe in square ABCD connecting de and CE=
2. As shown in the figure, in the quadrilateral ABCD, point E is on BC, ab ‖ De, ∠ B = 78 ° and ∠ C = 60 °, then the degree of ∠ EDC is () A. 42°B. 60°C. 78°D. 80°
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