The radius of circle a is 2 cm, and the diameter of circle B is 4 cm. Are the perimeter of the two circles equal?
Equal, because the diameter of the circle is twice the radius, so the two circles are the same, that is, the perimeter is equal, the area is equal
RELATED INFORMATIONS
- 1. First simplify and then calculate, as follows Given x = (√ 3 - √ 2) \ (√ 3 + √ 2), y = (√ 3 + √ 2) \ (√ 3 - √ 2), find the value of x ^ 2 + 2XY + y ^ 2 and X / y + Y / X
- 2. How to play long dash
- 3. The perimeter of a rectangle is 24cm. If the length of the rectangle is reduced by 2cm and the width is increased by 3cm, it will become a square. Find the area of the original rectangle? Use x solution
- 4. It is known that the equation of X, where the square of x plus (2m minus 1) x plus the square of M is equal to 0, has two real roots x 1 and x 2
- 5. 6 / 11 △ () 6 / 16 × 4 / 17 5 / 16 3 / 17 6 / 39 / 4 / 4 / 4 1 / 4 9 / 4 × 4 / 1 Fill in ">" < "=" in () for the quickest answer
- 6. How many hours is 1600 minutes in three? Thank you very much,
- 7. On the roots of equations and the zeros of functions 1. It is known that the real numbers a, B and C are three numbers in the domain of y = f (x), and satisfy a
- 8. Solution equation (x + 6) (X-7) = 14
- 9. How to solve the equation (x-3) + (3x-3) = 50
- 10. It is known that there are only six integer solutions to the inequality system X − a > 03 − 2x > 0, then the value range of a is () A. (-∞,-4)B. [-5,-4)C. (-5,+∞)D. (−5,−32)
- 11. If point a (- 2, Y1) and point B (- 1, Y2) are both on the image with inverse scale function y = - 2 / x, then the size relationship between Y1 and Y2 is y1
- 12. As shown in the figure, the image of the first-order function Y1 = x + 1 and the image of the inverse scale function y2 = KX (k is a constant and K ≠ 0) pass through point a (m, 2) (1) find the coordinates of point a and the expression of the inverse scale function; (2) compare directly with the image: when x > 0, the sizes of Y1 and Y2
- 13. Find the intersection coordinates a and B of the inverse scale function y = 2 / X and the linear function y = 2x-1, and find the area of the triangle AOB
- 14. Let the image of inverse scale function y = K / X and linear function y = ax + 1 intersect at a (- 1,2) B (2, - 1), and the area of triangle abo (o is the origin of coordinates)
- 15. How to calculate the area of the triangle formed by the intersection of the first-order function and the inverse scale function and the origin of the coordinate?
- 16. How to solve the triangle area of inverse proportion function
- 17. Analytic expression of inverse proportion function of triangle area
- 18. The relationship between triangle area and K value in inverse scale function image I know that the area of the triangle enclosed by the points on the image and the coordinate axis perpendicular to the inverse scale function is equal to half of the area of the triangle. But if there is a point on the image, another point is at the origin, and the three sides are not perpendicular to the coordinate axis, is this conclusion true?
- 19. As shown in the figure, the vertex B of RT △ ABC is on the image with inverse scale function y = 12x, and the edge AC is on the x-axis. It is known that ∠ ACB = 90 °, a = 30 ° and BC = 4
- 20. It is known that the three vertices of triangle ABC are on the image with inverse scale function y = 1 / X (1) Let a (x1, Y1), B (X2, Y2), C (X3, Y3), find the linear equation of the height on the AB side and the height on the BC side If the title, the detailed process is appropriate, thank you