Let the image of inverse scale function y = K / X and linear function y = ax + 1 intersect at a (- 1,2) B (2, - 1), and the area of triangle abo (o is the origin of coordinates)

Let the image of inverse scale function y = K / X and linear function y = ax + 1 intersect at a (- 1,2) B (2, - 1), and the area of triangle abo (o is the origin of coordinates)

Substituting point a (or point B) into the analytic expression of the first-order function, we can get a = - 1, so the analytic expression of the first-order function is y = - x + 1. Let the intersection of the first-order function and the X axis be c. when y = 0, - x + 1 = 0, we can get x = 1, so C (1,0) so the area of triangle ABO = triangle AOC + triangle BOC = 1 / 2 × 1 × 2 + 1 / 2 × 1 × 1 = 1.5