It is known that the image of y = x-4 intersects with the x-axis at a, and it intersects with the image of y = KX + B at point C. the abscissa of point C is 3, y = KX + B intersects with the x-axis at B, and the face of triangle ABC If the area is 2 / 5, find the analytic formula of y = KX + B
The coordinate of a is (4,0) y = KX + B, which intersects with the starting point C, so the coordinate of C is y = x-4, and the abscissa is 3. Then the coordinate of C is (3, - 1) triangle ABC area = 5 / 2 = AB length * half of the absolute value of the ordinate of C, that is, 1 / 2 * AB = 5 / 2Ab = 5
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