Take the point P on the image of the linear function y = - x + 3, make PA perpendicular to the X axis and Pb perpendicular to the Y axis. If the s rectangle paob = 2, how many points can be found

Take the point P on the image of the linear function y = - x + 3, make PA perpendicular to the X axis and Pb perpendicular to the Y axis. If the s rectangle paob = 2, how many points can be found

Let P coordinate be (x, y), then | XY | = 2, and y = x + 3, so | x ^ 2 + 3x | = 2, so x ^ 2 + 3x + 2 = 0 or x ^ 2 + 3x-2 = 0. So the solution is x = - 1 or X = - 2 or x = [- 3 + 17 ^ (1 / 2)] / 2 or x = [- 3-17 ^ (1 / 2)] / 2, so there are four P points, and the corresponding y can be obtained by y = x + 3