As shown in the figure, the vertex B of RT △ ABC is on the image with inverse scale function y = 12x, and the edge AC is on the x-axis. It is known that ∠ ACB = 90 °, a = 30 ° and BC = 4

When y = 4, x = 3, that is, the coordinates of point B are (3,4), ‖ OC = 3. In RT △ ABC, ∠ ACB = 90 °, a = 30 °, BC = 4, ‖ AB = 2BC = 8, AC = 3bC = 43, OA = ac-oc = 43-3. Let AB and y-axis intersect at point D. ∫ OD ‖ BC, ‖ ODBC = oaac, that is, OD4 = 43-343, and the solution of OD = 4-3, that is, the solution of the shadow part is obtained The area is: 12 (OD + BC) · OC = 12 (4-3 + 4) × 3 = 12-323

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