As shown in the figure, the image of the first-order function Y1 = x + 1 and the image of the inverse scale function y2 = KX (k is a constant and K ≠ 0) pass through point a (m, 2) (1) find the coordinates of point a and the expression of the inverse scale function; (2) compare directly with the image: when x > 0, the sizes of Y1 and Y2

(1) Substituting the coordinate of a into Y1 = x + 1, M + 1 = 2, M = 1, so the coordinate of point a is (1, 2), substituting the coordinate of point a into y2 = KX, 2 = K1, k = 2, then the expression of inverse proportional function y2 = 2x; (2) combining with the function image, we can get: when 0 < x < 1, Y1 < Y2; when x = 1, Y1 = Y2; when x > 1, Y1 > Y2

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