Given the positive scale function y = KX, (1) if the function image passes through the second and fourth quadrants, then the value range of K
In the second quadrant and the fourth quadrant, the inverse scale function image has the following characteristics:
When x > 0, y < 0, the image is in the fourth quadrant
When x < 0, y > 0, the image is in the second quadrant
Therefore, the inverse scale function xy = k < 0
That is, when k < 0, the inverse scale function image is in the second and fourth quadrants
RELATED INFORMATIONS
- 1. Given that the graph of a function y = kx-3 is parallel to the straight line y = 2x + 1, (1) find the analytic expression of the function, (2) which quadrants does the graph of the function pass through
- 2. As shown in the figure, it is known that the image of the line y = x + 3 intersects with the X and Y axes at two points a and B. the line L passes through the origin and intersects with the line AB at point C. the area of △ AOB is divided into two parts of 2:1. The analytical formula of the line L is obtained
- 3. The image of the function y = 3 ^ X and y = - 3 ^ (- x) is symmetric about which of the following figures a.x axis b.y axis C. straight line y = x D. origin center is symmetric
- 4. As shown in the figure, a and C are any two points symmetrical about the origin on the image of the function y = KX (K ≠ 0), AB and CD are perpendicular to the X axis, and the perpendicular feet are B and D respectively. Then the area s of the quadrilateral ABCD is () A. k2B. 2kC. 4kD. k
- 5. The image of the function y = 3 ^ X and y = - 3 ^ (- x) is symmetric about a.x axis b.y axis C. line y = x D. origin
- 6. The length of a rectangle is x, the width is y, the perimeter is 16, and the area is 15. Find the value of X & # 179; y + 2x & # 178; Y & # 178; + XY & # 179
- 7. The area of a rectangle is X & # 178; + xy-12y & # 178;, and its length is x + 4Y
- 8. Given that the length of the rectangle is x, the width is y, the perimeter is 16, and the area is 15, find the value of x ^ 3 y + 2x ^ 2Y ^ 2 + XY ^ 3
- 9. The linear equation of y = 2x-1 about X-axis symmetry, about Y-axis symmetry and about origin
- 10. Taking a circle as an example, this paper discusses the characteristics of the equation of a curve if it is symmetrical about the X axis, Y axis, coordinate origin and passes through the coordinate origin? Based on the above conclusions, the principles and methods of establishing the Department are discussed
- 11. The graph of the function y = KX + B is parallel to the straight line y = 2x and passes through the point (0,3)
- 12. The graph of the function y = KX + B is parallel to the straight line y = 2x and passes through the point (0,3)
- 13. It is known that the image of a first-order function is parallel to the line y = 2x, and it intersects with the line y = - 3x-5 / 2 and has the same point on the y-axis
- 14. The value of M is calculated on the x-axis through the intersection point of the image of the first-order function y = 3x + m and the image of the first-order function y = 4-2x
- 15. We know the quadratic function y = x ^ 2-mx-4. (1) prove that the image of the function must have two different intersections with the X axis; (2) let the coordinates of the intersection of the image of the function and the X axis be (x1,0), (x2,0), and 1 / X1 + 1 / x2 = - 1, find the value of M, and find the vertex coordinates of the function image. (please answer with junior high school mathematics knowledge)
- 16. It is known that the image of a linear function y = - 0.5x is parallel, and the intersection point (0, - 3) of the function and the Y axis is obtained
- 17. It is known that the image of a function of degree passes through point a [2,3] and the ordinate of the intersection point with the y-axis is 4 Be detailed as soon as possible
- 18. Given that the image of a function y = KX + B passes through points m (- 1,1) and (0,2), let the image intersect with the x-axis at point a and with the y-axis at point B: Q: on the x-axis Given that the image of a function y = KX + B passes through point m (- 1,1) and point (0,2), let the image intersect with X axis at point a and Y axis at point B: Q: is there a point P on X axis, so that the triangle ZBP is an isosceles triangle? If it exists, the coordinates of all the points P that meet the conditions can be obtained. If not, please give reasons
- 19. Given that the image of the first-order function y = KX + B passes through the point (- 2,5) and intersects with the y-axis at the point P, the line y = - 12x + 3 intersects with the y-axis at the point Q, and the point q is exactly symmetric with the point P about the x-axis, the expression of the first-order function is obtained
- 20. Given that the image of the first-order function y = KX + B passes through the point (- 2,5) and intersects with the y-axis at the point P, the line y = - 12x + 3 intersects with the y-axis at the point Q, and the point q is exactly symmetric with the point P about the x-axis, the expression of the first-order function is obtained