It is known that the image of a function of degree passes through point a [2,3] and the ordinate of the intersection point with the y-axis is 4 Be detailed as soon as possible
Let the function relation be y = KX + B
According to the meaning of the problem: the image of a function of degree passes through a (2,3), (0,4)
Then 3 = 2K + B
4=b
The solution is: k = - 0.5, B = 4
So y = - 0.5x + 4
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