Given that the graph of a function y = kx-3 is parallel to the straight line y = 2x + 1, (1) find the analytic expression of the function, (2) which quadrants does the graph of the function pass through

Given the linear function y = kx-3, the image is parallel to the line y = 2x + 1
That is, the slopes are equal, so k = 2
The analytic expression of the function is y = 2x-3
The slope of the function is greater than 0, B = - 3, so it passes through one, three and four quadrants

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1. As shown in the figure, it is known that the image of the line y = x + 3 intersects with the X and Y axes at two points a and B. the line L passes through the origin and intersects with the line AB at point C. the area of △ AOB is divided into two parts of 2:1. The analytical formula of the line L is obtained
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