It is known that the image of a first-order function is parallel to the line y = 2x, and it intersects with the line y = - 3x-5 / 2 and has the same point on the y-axis

It is known that the image of a first-order function is parallel to the line y = 2x, and it intersects with the line y = - 3x-5 / 2 and has the same point on the y-axis

The image of a linear function is parallel to the line y = 2x
The function is y = 2x + B
The intersection with the line y = - 3x-2 / 5 and the same point on the Y axis
Let x = 0, y = - 5
Substitute (0, - 5) into y = 2x + B to get
b=-5
So the equation of the function is y = 2x-5