For the curve X = y ^ 4-y (a), find dy / DX (b). When the slope is 1 / 3, find the tangent equation

(a)
X=y^4-y
dx=4y^3dy-dy
dx=(4y^3-1)dy
dy/dx=1/(4y^3-1)
(b) K = 1 / 3, that is, 1 / (4Y ^ 3-1) = 1 / 3
4y^3-1=3
y=1
So x = 1-1 = 0
Tangent (0,1)
y-1=x/3
x-3y+3=0

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