（2x^2)dy/dx+y=4y^3 The original equation is reduced to (1 / 2x ^ 2) DX = (1 / 4Y ^ 3-y) dy Integral on both sides is - 1 / 6x ^ 3 + C = (1 / 12Y ^ 2-1) ln (4Y ^ 3-y)

(2x ^ 2) dy / DX + y = 4Y ^ 3, separate variables to get dy / (4Y ^ 3-y) = DX / (2x ^), 1 / (4Y ^ 3-y) = 1 / [y (2Y + 1) (2y-1)] = - 1 / y + 1 / (2Y + 1) + 1 / (2y-1), х ln (2Y + 1) + ln (2y-1) - 2lny = - 1 / x + C, х (4Y ^ - 1) / y ^ = e ^ (- 1 / x + C)

（2x^2)dy/dx+y=4y^3 The original equation is reduced to (1 / 2x ^ 2) DX = (1 / 4Y ^ 3-y) dy Integral on both sides is - 1 / 6x ^ 3 + C = (1 / 12Y ^ 2-1) ln (4Y ^ 3-y)

（2x^2)dy/dx+y=4y^3 The original equation is reduced to (1 / 2x ^ 2) DX = (1 / 4Y ^ 3-y) dy Integral on both sides is - 1 / 6x ^ 3 + C = (1 / 12Y ^ 2-1) ln (4Y ^ 3-y)

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