Given the equation X3 + 3xy + Y3 = 0, determine y as the function of X to find dy / DX

Both sides take derivatives of X. note that y is a function of X
3x^2+3(y + x* dy/dx) + 3y^2 * dy/dx = 0
So dy / DX = - (x ^ 2 + y) / (x + y ^ 2)
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