(2x^2)dy/dx+y=4y^3 將原方程化為(1/2x^2)dx=(1/4y^3-y)dy 兩邊積分得-1/6x^3+c=(1/12y^2-1)ln(4y^3-y)

(2x^2)dy/dx+y=4y^3 將原方程化為(1/2x^2)dx=(1/4y^3-y)dy 兩邊積分得-1/6x^3+c=(1/12y^2-1)ln(4y^3-y)

(2x^2)dy/dx+y=4y^3,分離變數得dy/(4y^3-y)=dx/(2x^),1/(4y^3-y)=1/[y(2y+1)(2y-1)]=-1/y+1/(2y+1)+1/(2y-1),∴ln(2y+1)+ln(2y-1)-2lny=-1/x+c,∴(4y^-1)/y^=e^(-1/x+c).您做的不對.