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The triangle ABC is an isosceles triangle with the angle BAC = 70 ° and the semicircle with the diameter AB intersects at point D and BC at point E The degree of arc ad, Arc de and arc be A is on the top, B is on the left, C is on the right, D is on AC, e is on BC
Draw your own picture, mark the angle, and you'll know after you finish
20,35,34
RELATED INFORMATIONS
- 1. If two numbers are randomly taken out in the interval (0, 1), the probability that the sum of the two numbers is less than 56 is zero______ ．
- 2. If two numbers are randomly taken out in the interval (0, 1), the probability that the sum of the two numbers is less than 65 is zero______ ．
- 3. If two numbers are randomly taken out in the interval (0, 1), the probability that the sum of the two numbers is less than 56 is zero______ ．
- 4. If two numbers are randomly taken out in the interval (0, 1), the probability that the sum of the two numbers is less than 65 is zero______ ．
- 5. If we take a random number x in the interval [0, π], then the probability of the event SiNx + 3cosx ≤ 1 is 0______ ．
- 6. If we take a number x randomly in the interval (0, π), the probability of the event "SiNx + root 3cosx ≤ 1" is zero
- 7. If we randomly take a number x in the interval [0, π], then the probability of the event "SiNx ≥ cosx" is () A. 14B. 12C. 34D. 1
- 8. If we randomly take a number a in the interval [- 5, 5], then we just make 1 be a solution of the inequality 2x2 + ax-a2 < 0 about X, and the probability of its solution is 0______ ．
- 9. If the absolute value of the difference between a number and 2 is equal to the opposite of the difference between it and 2, then what is the range of the number?
- 10. If any real number a is taken in the interval (- 1,1) and any real number B is taken in the interval (0,1), then the probability of the intersection of the line ax by = 0 and the circle (x-1) 2 + (Y-2) 2 = 1 is () A. 38B. 516C. 58D. 316
- 11. As shown in the figure, it is known that △ ABC is inscribed in circle O, e is the midpoint of arc BC, and AE intersects BC in D Why ∧ CBE = ∧ BAE?
- 12. As shown in the figure, AB is a fixed length line segment, the center O is the midpoint of AB, AE and BF are tangent points, e and F are tangent points, satisfying AE = BF. Take point G on EF, and point G is the extension line of tangent intersection AE and BF at points D and C. when point G moves, let ad = y, BC = x, then the functional relationship between Y and X is () A. Positive proportion function y = KX (k is constant, K ≠ 0, X ＞ 0) B. primary function y = KX + B (k, B is constant, KB ≠ 0, X ＞ 0) C. inverse proportion function y = KX (k is constant, K ≠ 0, X ＞ 0) d. quadratic function y = AX2 + BX + C (a, B, C is constant, a ≠ 0, X ＞ 0)
- 13. As shown in the figure, take the waist ab of the isosceles triangle ABC as the diameter to draw a semicircle o, intersecting AC with E and BC with D Verification: 1. D is the midpoint of BC 2. If the angle BAC = 50 degrees, calculate the degree of arc BD
- 14. Known: as shown in the figure, take one side BC of triangle ABC as the diameter to make a semicircle, intersect AB at e, pass through e to make a semicircle, the tangent of O is just perpendicular to AC, try to determine the size relationship between BC and AC, and prove your conclusion The graph is a regular triangle, the upper corner is C, the left corner is B, the right corner is a, the tangent line is perpendicular to AC, and the intersection point is f
- 15. As shown in the figure, in the triangle ABC, AB is equal to AC, and the semicircle o with AC as the diameter intersects AB and BC at points D and e respectively 2. If the angle cod = 80 degrees, find the degree of the angle bed
- 16. As shown in the figure: in △ ABC, the semicircle o with ab as the diameter intersects AC BC at the point de. prove that the triangle ode is an equilateral triangle
- 17. As shown in the figure, in △ ABC, ab = AC, the semicircle o with AC as the diameter intersects AB and BC at points D and e respectively. (1) prove that point E is the midpoint of BC; (2) if ∠ cod = 80 °, calculate the degree of ∠ bed
- 18. AB is the diameter of semicircle o, C is the point on semicircle o which is different from a and B, CD ⊥ AB, perpendicular foot is D, ad = 2, CB = 4 * radical 3, then CD = -? The root number can't be typed = =, by the way, how to type the root number--
- 19. It is known that AB in semicircle o is the diameter ad = DC ∠ cab = 30 ° AC = 3 root sign 3, and the length of ad is calculated Don't use sin to solve the problem that we didn't learn
- 20. As shown in the figure, in the semicircle AOB, ad = DC, ∠ cab = 30 °, AC = 23, the length of ad is calculated