As shown in the figure, in the triangle ABC, AB is equal to AC, and the semicircle o with AC as the diameter intersects AB and BC at points D and e respectively 2. If the angle cod = 80 degrees, find the degree of the angle bed

As shown in the figure, in the triangle ABC, AB is equal to AC, and the semicircle o with AC as the diameter intersects AB and BC at points D and e respectively 2. If the angle cod = 80 degrees, find the degree of the angle bed

(1) Link AE
∵ AC is the diameter of circle o
∴∠AEC=90°
And ∵ AB = AC
E is the midpoint of BC (isosceles triangle with three lines in one)
(2)
∵∠CAD=1/2∠COD=1/2×80°=40°
∴∠BED=∠CAD=40°
(a circle inscribed with a quadrilateral is equal to a non adjacent inner angle)