As shown in the figure, it is known that △ ABC is inscribed in circle O, e is the midpoint of arc BC, and AE intersects BC in D Why ∧ CBE = ∧ BAE?

prove:
∵ e is the midpoint of arc BC
Ψ arc be = arc CE
∴∠CBE=∠BAE
∵∠E=∠E
∴△ECD∽△EAB
∴BE/AE=ED/BE
∴BE²=ED *EA
PS: equal circle angle of equal arc

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