If two numbers are randomly taken out in the interval (0, 1), the probability that the sum of the two numbers is less than 65 is zero______ .
Let the two numbers be x and Y respectively, we can get 0 < x < 1 and 0 < y < 1. The area of the point (x, y) satisfying the condition is the interior of the square whose abscissa and ordinate are between (0, 1), that is, the interior of the square oabc as shown in the figure, and its area is s = 1 × 1 = 1. If the sum of the two numbers is less than 65, that is, x + y < 65, the corresponding area is
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- 1. If two numbers are randomly taken out in the interval (0, 1), the probability that the sum of the two numbers is less than 56 is zero______ .
- 2. If two numbers are randomly taken out in the interval (0, 1), the probability that the sum of the two numbers is less than 65 is zero______ .
- 3. If we take a random number x in the interval [0, π], then the probability of the event SiNx + 3cosx ≤ 1 is 0______ .
- 4. If we take a number x randomly in the interval (0, π), the probability of the event "SiNx + root 3cosx ≤ 1" is zero
- 5. If we randomly take a number x in the interval [0, π], then the probability of the event "SiNx ≥ cosx" is () A. 14B. 12C. 34D. 1
- 6. If we randomly take a number a in the interval [- 5, 5], then we just make 1 be a solution of the inequality 2x2 + ax-a2 < 0 about X, and the probability of its solution is 0______ .
- 7. If the absolute value of the difference between a number and 2 is equal to the opposite of the difference between it and 2, then what is the range of the number?
- 8. If any real number a is taken in the interval (- 1,1) and any real number B is taken in the interval (0,1), then the probability of the intersection of the line ax by = 0 and the circle (x-1) 2 + (Y-2) 2 = 1 is () A. 38B. 516C. 58D. 316
- 9. In the interval [0,1], take any two numbers a and B, and the probability of two real numbers of equation x2 + ax + B2 = 0 is () A. 18B. 14C. 12D. 34
- 10. If the real numbers x and Y belong to [0,1], then the probability that the square of X + the square of Y is greater than 1 is zero
- 11. If two numbers are randomly taken out in the interval (0, 1), the probability that the sum of the two numbers is less than 56 is zero______ .
- 12. The triangle ABC is an isosceles triangle with the angle BAC = 70 ° and the semicircle with the diameter AB intersects at point D and BC at point E The degree of arc ad, Arc de and arc be A is on the top, B is on the left, C is on the right, D is on AC, e is on BC
- 13. As shown in the figure, it is known that △ ABC is inscribed in circle O, e is the midpoint of arc BC, and AE intersects BC in D Why ∧ CBE = ∧ BAE?
- 14. As shown in the figure, AB is a fixed length line segment, the center O is the midpoint of AB, AE and BF are tangent points, e and F are tangent points, satisfying AE = BF. Take point G on EF, and point G is the extension line of tangent intersection AE and BF at points D and C. when point G moves, let ad = y, BC = x, then the functional relationship between Y and X is () A. Positive proportion function y = KX (k is constant, K ≠ 0, X > 0) B. primary function y = KX + B (k, B is constant, KB ≠ 0, X > 0) C. inverse proportion function y = KX (k is constant, K ≠ 0, X > 0) d. quadratic function y = AX2 + BX + C (a, B, C is constant, a ≠ 0, X > 0)
- 15. As shown in the figure, take the waist ab of the isosceles triangle ABC as the diameter to draw a semicircle o, intersecting AC with E and BC with D Verification: 1. D is the midpoint of BC 2. If the angle BAC = 50 degrees, calculate the degree of arc BD
- 16. Known: as shown in the figure, take one side BC of triangle ABC as the diameter to make a semicircle, intersect AB at e, pass through e to make a semicircle, the tangent of O is just perpendicular to AC, try to determine the size relationship between BC and AC, and prove your conclusion The graph is a regular triangle, the upper corner is C, the left corner is B, the right corner is a, the tangent line is perpendicular to AC, and the intersection point is f
- 17. As shown in the figure, in the triangle ABC, AB is equal to AC, and the semicircle o with AC as the diameter intersects AB and BC at points D and e respectively 2. If the angle cod = 80 degrees, find the degree of the angle bed
- 18. As shown in the figure: in △ ABC, the semicircle o with ab as the diameter intersects AC BC at the point de. prove that the triangle ode is an equilateral triangle
- 19. As shown in the figure, in △ ABC, ab = AC, the semicircle o with AC as the diameter intersects AB and BC at points D and e respectively. (1) prove that point E is the midpoint of BC; (2) if ∠ cod = 80 °, calculate the degree of ∠ bed
- 20. AB is the diameter of semicircle o, C is the point on semicircle o which is different from a and B, CD ⊥ AB, perpendicular foot is D, ad = 2, CB = 4 * radical 3, then CD = -? The root number can't be typed = =, by the way, how to type the root number--