As shown in the figure, in the plane rectangular coordinate system, the analytical expression of the straight line L is y = - 2x-8, L respectively intersects at two points a and B on the x-axis and y-axis, and the point P (0, K) is a moving point on the negative half axis of the y-axis. Take P as the center of the circle and 3 as the radius to make the circle P 2) When k is the value, the triangle with the two intersections of circle P and line L and the center of circle P as the vertex is an equilateral triangle? Come on, it's urgent,

As shown in the figure, in the plane rectangular coordinate system, the analytical expression of the straight line L is y = - 2x-8, L respectively intersects at two points a and B on the x-axis and y-axis, and the point P (0, K) is a moving point on the negative half axis of the y-axis. Take P as the center of the circle and 3 as the radius to make the circle P 2) When k is the value, the triangle with the two intersections of circle P and line L and the center of circle P as the vertex is an equilateral triangle? Come on, it's urgent,

There is nothing wrong with the calculation process upstairs, but another one is missing
K1 = (3 / 2 radical 15) - 8 P1 between ob
K2 = - (3 / 2 radical 15) - 8 P2 below point B
The calculation method is the same. P1 and P2 are symmetrical about point B