The standard equation of a circle whose center is on 2x-y = 3 and tangent to two coordinate axes Two equations

The equation for finding the circle whose center is on the straight line 2x-y-3 = 0 and tangent to two coordinate axes
The circle is tangent to the two axes
So the circular equation is (x-a) & sup2; + (Y ± a) & sup2; = A & sup2;
The center of the circle (a, ± a) is on the line 2x-y-3 = 0
When the center of the circle is (a, a)
Easy to find a = 3
When the center of the circle is (a, - a)
Easy to find a = 1
So the equation is (x-3) & sup2; + (Y-3) & sup2; = 9
Or (x-1) & sup2; + (y + 1) & sup2; = 1

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