Find the standard equation of the circle whose center is on the line 2x-y-3 = 0 and tangent to the X axis at the point (- 2,0) The standard equation of the circle whose center is on the line 2x-y-3 = 0 and tangent to the x-axis at the point (- 2,0)

Find the standard equation of the circle whose center is on the line 2x-y-3 = 0 and tangent to the X axis at the point (- 2,0) The standard equation of the circle whose center is on the line 2x-y-3 = 0 and tangent to the x-axis at the point (- 2,0)

A:
Tangent to X-axis at (- 2,0)
Then the center of the circle must be on the line x = - 2
The coordinate of the center of the circle is (- 2, - 7) when the solution is combined with the line 2x-y-3 = 0
So: the radius of the circle r = 0 - (- 7) = 7
So the equation of circle is: (x + 2) &# 178; + (y + 7) &# 178; = 49