Known: as shown in the figure, in triangle ABC, angle ACB = 90, AC = BC, CD / / AB, and ab = ad

Known: as shown in the figure, in triangle ABC, angle ACB = 90, AC = BC, CD / / AB, and ab = ad

It is proved that CE is perpendicular to AB and DF is perpendicular to AB and F
∵CD∥AB.
∴DF=CE.
∵AC=BC,∠ACB=90°.
Therefore, DF = CE = AB / 2 = ad / 2
In a right triangle, if a right side is equal to half of the hypotenuse, the opposite angle is 30 degrees
∴∠CAD=∠CAB-∠DAF=15°.
Therefore, ∠ BAC = 45 ° = 3 ∠ CAD