In equilateral △ ABC, points D and E are on edges BC and ab respectively, and BD = ae

It is proved that in △ ABC, CA = AB, ∠ CAE = ∠ abd, and ∵ AE = BD, in △ CAE and △ abd, AE = BD, B = ∠ caeca = AB, ≌ CAE ≌ Δ abd (SAS), ad = CE

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1. As shown in the figure, in the triangle ABC, ad is vertical to BC, be is vertical to AC, CF is vertical to AB, and the perpendicular feet are D, e, F. BC equals 16, ad equals 3, CF equals 6. Calculate the circumference of ABC
2. As shown in the figure, the perimeter of the right angle △ ABC is 18. There are five small right triangles in it, and the right sides in the same direction are parallel to each other. Find the sum of the perimeter of the five small right triangles
3. In RT △ ABC, the bisector be, the perpendicular BC, the perpendicular foot E and BC = 20 are used to calculate the perimeter of △ Dec
4. In △ ABC, ab = AC, the vertical bisector of AB intersects at point D and AC intersects at point e. it is known that the perimeter of △ BCE is 8 and ac-bc = 2. The lengths of AB and BC are obtained
5. In the triangle ABC, if AB = 3, AC = 8, the length of BC is odd, try to find the perimeter of the triangle ABC
6. In triangle ABC, if AB = 3cm, AC = 8cm, the length of BC is odd, try to find the perimeter of angle ABC
7. If AB = AC = 10 in △ ABC is known, de bisects AB vertically and intersects AC with E. if the perimeter of △ BEC is known to be 16, find the perimeter of △ ABC
8. AC = AB, de bisects AB vertically, intersects AB with D, intersects AC with E. if the perimeter of triangle ABC is 28, BC = 8, find the perimeter of triangle bec
9. Given the angle ABC = angle c, De, the circumference of the intersection AC of AB and the triangle BEC of point E is 10, AC BC = 2 Given that the angle ABC = angle c, de bisects the intersection of AB vertically, the perimeter of AC and point e triangle BEC is 10, AC BC = 2, find the perimeter of triangle ABC! But I just can't think of it. It's more difficult. I think of it. Just give me an idea!
10. In △ ABC, ab = AC,
11. As shown in the figure, D is the midpoint of the waist AC of the isosceles right triangle ABC, connecting BD, making AE through a, vertical BD, side BC at e, try to explain, ∠ ADB = ∠ CDE
12. On the site of right triangle ABC, the angle bisector AE of ∠ B = 90 ° AB = AC intersects at point E Party A and Party B start from a at the same time and go along the AC and A-B-E lines at the same speed. Party A's destination is C and Party B's destination is e. please judge which of Party A and Party B arrive at their respective destinations first? And explain the reason
13. If △ ABC ∽ CAD, ∠ ACB = ∠ ADC = 90, BC = a, AC = B, ab = C, then CD is equal to Please use letters Thank you in advance
14. Known: as shown in the figure, in triangle ABC, angle ACB = 90, AC = BC, CD / / AB, and ab = ad
15. As shown in the figure, in RT △ ABC, ∠ C = 90 °, am is the middle line on the side of BC, sin ∠ cam = 35, then the value of tanb is () A. 32B. 23C. 56D. 43
16. In known acute triangle ABC, sin (a + b) = 3 / 5, sin (a-b) = 1 / 5 In known acute triangle ABC, sin (a + b) = 3 / 5, sin (a-b) = 1 / 5 (1) Verification: Tan a = 2tanb; (2) Let AB = 3, find the height on the edge of ab
17. In the triangle ABC, the angle c = 90 degrees, BC = AC = 2, D is the midpoint of the AC side, find sin angle, Tan angle DBA
18. In the triangle ABC, ADA is perpendicular to D, angle bad = a, angle CAD = B= sina.sinb + cosa.sinb
19. In △ ABC, ∠ C = 90 °, De is the vertical bisector of AB on the line side, and the degree ratio of ∠ DAE to ∠ DAC is 2:1, so the degree of ∠ B can be calculated
20. As shown in the figure, in △ ABC, ∠ C = 90 °, the vertical bisector of AB intersects at point D, AB intersects at point E, the degree ratio of ∠ DAE and ∠ DAC is 2:1, and the degree of ∠ B is calculated