AC = AB, de bisects AB vertically, intersects AB with D, intersects AC with E. if the perimeter of triangle ABC is 28, BC = 8, find the perimeter of triangle bec

AC = AB, de bisects AB vertically, intersects AB with D, intersects AC with E. if the perimeter of triangle ABC is 28, BC = 8, find the perimeter of triangle bec

18 'according to the meaning of the title, the triangle Abe should be isosceles triangle, be = AE, so be + EC = AE + EC = AC, so the perimeter of the triangle BEC = be + EC + BC = AC + BC, according to the known conditions, AC = 10, so the perimeter is 18