Given the angle ABC = angle c, De, the circumference of the intersection AC of AB and the triangle BEC of point E is 10, AC BC = 2 Given that the angle ABC = angle c, de bisects the intersection of AB vertically, the perimeter of AC and point e triangle BEC is 10, AC BC = 2, find the perimeter of triangle ABC! But I just can't think of it. It's more difficult. I think of it. Just give me an idea!

Given the angle ABC = angle c, De, the circumference of the intersection AC of AB and the triangle BEC of point E is 10, AC BC = 2 Given that the angle ABC = angle c, de bisects the intersection of AB vertically, the perimeter of AC and point e triangle BEC is 10, AC BC = 2, find the perimeter of triangle ABC! But I just can't think of it. It's more difficult. I think of it. Just give me an idea!

Connect be
∵ e is on the vertical bisector of ab
∴EB=EA
The circumference of ∧ BCE = BC + CE + be = BC + AC = 10
That is, AC + BC = 10
And ac-bc = 2
∴AC=6,BC=4,AB=6
The circumference of ABC = 6 + 6 + 4 = 16