In RT △ ABC, the bisector be, the perpendicular BC, the perpendicular foot E and BC = 20 are used to calculate the perimeter of △ Dec
In RT △ ABC, a = 90 °∠ C = 45 ° and BC = 20
Then AB = AC = 10 √ 2
BD is the bisector of ABC
Then △ abd and △ EBD are similar triangles
That is, ad = De, ab = be
Then the perimeter of △ Dec is CD + CE + de = CD + AD + bc-be = AC + bc-ab = BC = 20
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