The focus is (0,6) (0, - 6), and the hyperbolic standard equation is obtained through the point (2, - 5) | Math enthusiast | Mathematical art

The focus is (0,6) (0, - 6), and the hyperbolic standard equation is obtained through the point (2, - 5)

Hyperbola Y2 / a2-x2 / B2 = 1
a2+b2=36
25/a2-4/b2=1
The solution is A2 = 20, A2 = 45
So the hyperbolic standard equation: Y2 / 20-x2 / 16 = 1

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