Let the equation x2 / M-1 + Y2 / M + 3 = 1 denote hyperbola and find the value range of M one m-1>0,m+3>0, The solution is m > 1, M > - 3 The range of M is m > - 3 two (m-1)(m+3) Note that hyperbola is not ellipse. Explain the reasons and reasons for your choice
To understand the characteristics of hyperbola, the first solution is ellipse. In order to be hyperbola, M-1 and M + 3 must be positive and negative (judge the specific positive and negative situation according to the focus position), so they are the lion of the second solution
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- 1. The equation x2-m of 3-m + Y2 of 2 = 1 represents hyperbola, then the value range of M
- 2. Given hyperbola X & # 178; - Y & # 178; = 4, straight line L: y = K (x-1), try to determine the value range of real number k, so that (1) The line L and hyperbola have two common points (2) Line L and hyperbola have and only have one common point (3) There is no common point between line L and hyperbola
- 3. It is known that a focal point of an ellipse is f (1,1), the corresponding collimator is x + y-4 = 0, and the eccentricity is √ 2 / 2
- 4. If the eccentricity of the ellipse is 12, a focal point is f (3,0) and the corresponding guide line is X-1 = 0, then the elliptic equation is______ .
- 5. Given that the Quasilinear of the ellipse is x = 4, the corresponding focal coordinate is (2,0), and the eccentricity is 1 / 2, then the equation of the ellipse is?
- 6. The center and focus of an ellipse are o (0,0) and f (4,0) respectively, and the major half axis is 5 Want a detailed process The answer is x ^ 2 / 25 + y ^ 2 / 9 = 1
- 7. The focus of ellipse is on x-axis, the length of short axis is 2 √ 2, the eccentricity is 3 / 6, and the intersection of positive half axis of ellipse and x-axis and y-axis is a B
- 8. Suppose that the center of the ellipse is at the origin o, the focus is on the X axis, the eccentricity is (√ 2) / 2, and the sum of the distances from one point P to two focuses on the ellipse is equal to √ 6. (1) if the straight line x + y + m = 0 intersects the ellipse at two points a and B, and OA ⊥ ob, find the value of M?
- 9. It is known that the center of the ellipse is at the origin, the focus is on the y-axis, the focal length is 4, and the eccentricity is 2 / 3
- 10. It is known that the center of the ellipse is at the origin, the focus is on the y-axis, the focal length is 4, and the eccentricity is 2 / 3, It is known that the sum of the distances from a point on the ellipse with the focus on the x-axis and the center on the origin to the two focuses is 4. If the root of the eccentricity of the ellipse is 3 / 2, then the equation of the ellipse is
- 11. An example of hyperbola and its standard equation Examples are: When a shell explodes somewhere, the time of the explosion sound heard at a is 2 s later than that at B. It is known that the distance between AB and ab is 800 m and the sound velocity is 340 m / s. The equation of the explosion point curve is obtained (let the explosion point be p (x, y); establish a rectangular coordinate system so that AB is on the X axis, and point O coincides with the midpoint of line AB) In the process of solving the problem, there is one step "Because pa - Pb = 340 * 2 = 680 > 0, x > 0" I can't figure out why "pa - Pb = 340 * 2 = 680 > 0" can lead to "x > 0", and why to determine whether x is greater than 0?
- 12. It is known that there are two intersections between a straight line passing through the right focus of hyperbola x2a2-y2b2 = 1 (a > 0, b > 0) and the right branch of hyperbola with an inclination angle of 45 degrees, then the value range of eccentricity e of hyperbola is______ .
- 13. Given that the hyperbola and the square of ellipse X / 9 + the square of ellipse Y / 25 = 1 are in common focus, the sum of their eccentricities is 7 / 5, the hyperbolic equation is solved I'm sorry, but the difference between their eccentricities is 7 / 5
- 14. Proposition p: "the equation x2 + y2m = 1 is an ellipse with focus on the y-axis", proposition q: "the function f (x) = 43x3-2mx2 + (4m-3) x-m increases monotonically on (- ∞, + ∞)". If P ∧ Q & nbsp; is a false proposition and P ∨ Q is a true proposition, the range of M is obtained
- 15. To solve the hyperbolic equation with the vertex and focus of the ellipse as the focus and vertex respectively Urgent need process, thank you
- 16. : hyperbolic center in the origin, the focus on the X axis, through the point (2, - 3) and asymptote is y = positive and negative two-thirds x, autumn hyperbolic equation
- 17. The focus is (0,6) (0, - 6), and the hyperbolic standard equation is obtained through the point (2, - 5)
- 18. The standard equation of hyperbola with focus (0,6), (0, - 6) passing through points (2, - 5) Best to write the process! Thank you
- 19. The focus is (0, - 6), (0,6), and the hyperbolic standard equation passing through points (2, - 5) is () A. y220-x216=1B. x220−y216=1C. y216−x236=1D. x216−y236=1
- 20. It has a common focus with the hyperbola x ^ 2 / 16-y ^ 2 / 9 = 1, and the hyperbolic equation can be solved through the point (- 3 radical 2,4)