It has a common focus with the hyperbola x ^ 2 / 16-y ^ 2 / 9 = 1, and the hyperbolic equation can be solved through the point (- 3 radical 2,4)
x^2/16-y^2/9=1
a'²=16,b'²=9
Then c '² = 25
There is a public focus
So C & # 178; = 25
Then x & # 178; / A & # 178; - Y & # 178; / (25-A & # 178;) = 1
So 18 / a-178; - 16 / (25-a-178;) = 1
De denominator
450-18a²-16a²=25a²-a^4
a^4-59a²+450=0
(a²-9)(a²-50)=0
a²
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