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As shown in the figure, in △ ABC, the linear equation of the height on the BC side is x-2y + 1 = 0, and the linear equation of the bisector of ∠ A is y = 0. If the coordinates of point B are (1,2), the coordinates of point a and point C are obtained
Point a is the intersection of two lines y = 0 and x-2y + 1 = 0, the coordinates of point a are (- 1, 0).. KAB = 2 − 01 − (− 1) = 1. The equation of the bisector line of ∵ - A is y = 0, ∵ - KAC = - 1. The equation of line AC is y = - X-1. BC is perpendicular to x-2y + 1 = 0, ∵ KBC = - 2. The equation of line BC is Y-2 = - 2 (x-1). From y = - X-1, y = - 2x + 4, the solution of C (5, - 6).. the coordinates of point a and point C are obtained They are (- 1,0) and (5, - 6) respectively
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