Given the function f (x) = x ^ 2 * f '(2) + 5x, then f' (2) =? Derivative sequence Using the derivative method may involve the previous sequence All right? Why doesn't f '(2) on the right of the equation change after f (x) is derived

Given the function f (x) = x ^ 2 * f '(2) + 5x, then f' (2) =? Derivative sequence Using the derivative method may involve the previous sequence All right? Why doesn't f '(2) on the right of the equation change after f (x) is derived

f'(x)=2f'(2)x+5
So f '(2) = 4f' (2) + 5. The solution is. F '(2) = - 5 / 3
F '(2) denotes the derivative value, which is a constant. Don't be fooled by the title