Let z = √ (U & # 178; + V & # 178;), u = SiNx, v = e ^ x, find DZ / DX

dz/dx
=dz/du *du/dx +dz/dv *dv/dx
obviously
dz/du= u /√(u²+v²)
du/dx=cosx
dz/dv= v /√(u²+v²)
dv/dx=e^x
therefore
dz/dx
=u /√(u²+v²) *cosx +v /√(u²+v²) *e^x

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