If the derivative of the function f (x) = x ^ m + ax is f '(x) = 2x + 1, then the sum of the first ten terms of the sequence {1 / F (n)} (n ∈ n +) is

Derivation of F (x) = MX ^ (m-1) + A
So m = 2, a = 1
f(x)=x^2+x
For its split term 1 / F (n) = 1 / (x ^ 2 + x) = [1 / X-1 / (x + 1)]
It is easy to calculate s = (1-1 / 2 + 1 / 2-1 / 3 '' ', 1 / 10-1 / 11)
=10/11
I'm tired of typing

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