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dz/dx =dz/du *du/dx +dz/dv *dv/dx 顯然 dz/du= u /√(u²;+v²;) du/dx=cosx dz/dv= v /√(u²;+v²;) dv/dx=e^x 所以 dz/dx =u /√(u²;+v²;)*cosx +v /√(u²;+v²;)*e^x
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