When a car starts to move in a straight line at a constant acceleration of 2 meters per second, just at this moment a bicycle will go at a speed of 8 meters per second Come at a constant speed and drive past the car from behind. How long does it take for the car to catch up with the bicycle after it starts to move? What is the distance between the two cars? When does the car catch up with the bicycle? What is the speed of the car at this time?

When the speed of two cars is the same, the distance is the farthest
t=8/2=4s
S1=1/2at^2=16m
S2=8*4=32
Distance S = 16M
When the two parking spaces shift at the same time, catch up
S=1/2at^2=8t
So t = 8s
The velocity is v = 2 * 8 = 16m / s

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