The acceleration is A1. The motion time is T1. Then the acceleration is A2. After T2, the velocity is exactly zero. Then the average velocity of the object in the whole process can be expressed as? Why are 0.5a1t1 and 0.5a2t2 right

Because a1t1 = a2t2
In T1 period, V-0 = a1t1, the velocity accelerates from 0 to V, and in T2 period, the velocity decelerates from V to 0, 0-v = a2t2
The average velocity of T1 is A1 T1 / 2, the average velocity of T2 is A2 T2 / 2, the average velocity of T1 and T2 is equal, which is also the average velocity of the whole process

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