The acceleration is three meters to the second power, and the two cars move in the same direction The acceleration is three meters per second, and the car B lags behind two seconds. At the same place, the car B starts to move in a straight line with uniform acceleration, and the acceleration is four meters per second. The two cars move in the same direction, How long does it take for car B to catch up with car a? How far are they from the starting point?

The longest distance is when the speed of two cars is equal
That is: A1 * T1 = A2 * T2 and T1 = T2 + 2
So 3 (T2 + 2) = 4T2, T2 = 6S
Maximum distance S = (AT1 ^ 2-at2 ^ 2) / 2 = (3 * 8 ^ 2-4 * 6 ^ 2) / 2 = 24m
When catching up, S1 = S2
A1 * T1 ^ 2 = A2 * T2 ^ 2, namely 3 (T2 + 2) ^ 2 = 4T2 ^ 2

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