Ask a math problem (about high school function), It is known that the function y = f (x) defined on R satisfies f (0) ≠ 0. When x > 0, f (x) > 1, and for any a, B ∈ R, f (a + b) = f (a) f (b) (1) Verification: F (0) = 1; (2) Proof: for any x ∈ R, f (x) > 0; (3) It is proved that f (x) is an increasing function on R

Ask a math problem (about high school function), It is known that the function y = f (x) defined on R satisfies f (0) ≠ 0. When x > 0, f (x) > 1, and for any a, B ∈ R, f (a + b) = f (a) f (b) (1) Verification: F (0) = 1; (2) Proof: for any x ∈ R, f (x) > 0; (3) It is proved that f (x) is an increasing function on R

If a = 1, B = 0, then f (0 + 1) = f (0) * f (1); that is, f (1) = f (0) * f (1); if x = 1 > 0, then f (x) = f (1) > 1, then f (0) = 1; 2. If a = B, then f (0) = 1