A math problem (algebra problem) If Mn is a real number and one root of the equation x ^ 2 + MX + n = 0 is four times of the other root, then the relationship between M and N is () A.4m²+25n=0 B.2n²+25=0 C.4m²-25n=0 D.4n²-25n=0
x1+x2=-m
x1x2=n
x1=4x2
So there are: 5x2 = - m, 4x2 ^ 2 = n
4*(-m/5)^2=n
4m^2=25n
Choice: C
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