Given that X. y is a real number and satisfies (square of X + square of Y) x (square of X + square of Y -- 1) = 12, find the value of square of X + square of Y

Given that X. y is a real number and satisfies (square of X + square of Y) x (square of X + square of Y -- 1) = 12, find the value of square of X + square of Y

Let x ^ 2 + y ^ 2 = t, then t (t-1) = 12, so there is: T ^ 2-t-12 = 0, the solution is: T = - 3 or T = 4, so x ^ 2 + y ^ 2 = - 3 or 4