Trivariate linear equations 3x-y-z = 4 2x-3y-z = 12 x + y + Z = 6

Because 3x-y-z = 4
So z = 3x-y-4
Substitute 2x-3y-z = 12, x + y + Z = 6, respectively
That is, 2x-3y - (3x-y-4) = 12x + y + 3x-y-4 = 6
2x-3y- 3x+y+4=12 4x-4=6
-x-2y=8 x=2.5
x=2y-8
X = 2.5
x=2y-8
2.5=2y-8
y=5.25
z=3x-y-4=3x2.5-5.25-4=-1.75
So x = 2.5
y=5.25
z=-1.75
Stupid method, hope can help you!

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